Showing posts with label CHEMISTRY. Show all posts
Showing posts with label CHEMISTRY. Show all posts

Monday

Molecular weight And Mole

- “The molecular weight of substance is the relative mass of 1 molecule of it compared with 1/12 of the mass of an atom of carbon 12 isotope.” Molecular weight can be calculated by summing up the atomic weights of its constituent atoms. Eg. molecular weight of H2SO4 is 2 × 1 + 1 × 32 + 4 × 16 = 98
- According to Berzelius Hypothesis, “Equal volumes of all gases under the same conditions of temperature and pressure contain same number of atoms.”
- According to Avogadro’s Hypothesis, “Equal volume of all gases under the same conditions of temperature and pressure contain same no. of molecules.”
- Avogadro’s hypothesis leads us to following Important deductions.
1. Atomicity of elimentary gases.
2. Relationship between molecular weight and vapour density i.e. molecular weight of a gas is twice, it’s vapour density.
3. Gram molecular volume of gases i.e. 1 gram mole (molecular mass expressed in gram) of all gases occupies 22.4 litres at NTP. For example, 1 mole (32 gram) of oxygen or 1 mole (2 gram) of hydrogen at NTP occupies 22.4 litres.
4. 1 mole of any substance contains equal number of molecules called Avogadro’s number and is equal to 6.023 × 1023.
5. Determination of molecular formula from volumetric composition.
6. Mole Concept : Molecular mass expressed in terms of gram is called gram molecular mass or in short mole. The mole of substance can be calculated as,
No of Mole =
Mass in gram
Molecular wt.
E.g. Calculate the no. of mole in 80 gm of oxygen.
Solution: No of Mole =
Mass in gram
Molecular wt.
= 80/32 = 2.5
Determination of molecular weight by victor Meyer’s method :
We know that,
Molecular weight = 2 × vapour density and
Vapour density =
weight Vcc of substance at NTP
Weight Vcc of hydrogen at NTP

Sunday

Atomic Structure

The term atom was introduced by Dalton.
· In 1807, John Dalton proposed his famous atomic theory
Dalton’s Atomic Theory :
i. Matter is composed up extremely small particles called atoms.
ii. Atoms are indivisible. They can neither be created nor be destroyed.
iii. Atoms of the same element are alike in properties.
iv. Atoms combine in small whole numbers to form compound atoms.
Discovery of Subatomic Particles :
· J.J. Thomas (1897) concluded that cathode rays consist of a stream of fast moving negatively charged particles called electrons. He also determined the velocity of the electron and their charge-mass (e/m) ratio using different gases, and found the value 1.75875 × 1011CKg-1.
· In 1909 Millikan determined the charge and mass of the electron by using his famous oil drop technique and found the values 1.60206 × 10-19C and 9.1091 × 10-11Kg respectively.
· Goldstein (1886) used perforated cathode in the discharge tube and observed the emission of anode rays, which consist of positively charged particles known as protons. The charge and mass of the proton are found the values 1.6 × 10-19C and 1.672 × 10-27Kg respectively.
· In 1932, Chadwick discovered neutron, a neutral particle by the bombardment of α-particles on beryllium or boron.
J.J. Thomson’s Model :
According to this model, atom is compared with watermelon. Seeds are analogous to electrons and the edible part is the positive electrically.
Drawbacks of Watermelon model :
i. It cannot explain the stability of atom.
ii. Hydrogen spectra could not be explained.
Rutherford’s Experiment (Model) :
In 1911, Rutherford concluded that when α-particles struck on thin (4 × 10-5cm thick) sheet of gold :
-Most of the α-particle continued their straight path => Most part of atom is empty.
- Some α-particle deviated => The positive charge body of the atom is concentrated only at the centre of the atom called neucleus.
- Some α-particle (very few) bounced back => The positively charged mass is occupying a very small space.
The net outcome of Rutherford’s model gave the idea about nucleus (diameter 10-15m). He is the discoverer of nucleus. Hence the model is also known as nuclear model.
- We know that, nucleus has a diameter of the order of 10-15m while the atom has a diameter of the order of 10-10m.
Drawbacks of Rutherford’s model :
-Stability of atom couldn’t be explained. According to classical electrodynamics, accelerating particle emits radiation continuously. Therefore the revolving electron must loose energy continuously and the electron will steadily drift towards the nucleus and ultimately will fall into the nucleus collapsing the atom.
-Hydrogen Spectra couldn’t be explained.
=The atomic number is a fundamental property of the element and equal to number of protons in the nucleus i.e. equal to unit positive on the nucleus.
=The sum of the number of proton (Z) and neutrons (N) in a called the mass number (A) of the atom or A = N + Z. Hence proton, neutron and electron are the fundamental particles of an atom.
Bohr’s Model of Atom :
This theory, proposed by Neil Bohr, is based on both classical and quantum theory of planck. The important postulates of this model are:
i. The first postulate give the idea about circular orbits. An electron can revolve only in those orbits whose angular momentum (mvr) is an integral multiple of h/2π. i.e., mvr = nh/2π.
Where, m = mass of electron, v = velocity of electron, r = radius of orbit, h = Planck’s constant and n = number of orbit in which electron is present.
ii. So long as the electrons revolve in particular orbit, it neither gains nor looses energy. So the circular orbit is also known as stationary orbit or energy level.
iii. When electron jumps from one orbit to another, the difference in energy is emitted as radiation given by ΔE = E2 – E1= hv.
When electron jumps from lower energy level, it gains energy but loses when vice-versa.
Advantages of Bohr’s model :
Bohr’s theory satisfactorily explains the spectra of species having one electron, viz hydrogen atom, He+,Le2+ etc. Further his postulates can also be used for calculating :
i. Radii of various orbits of hydrogen atom like species, r =
n2h2
2me2z
= 0.529 × n2
z
where, 0.529 is the radius of the first orbit of hydrogen atom.
ii. The velocity of electron in an orbit , v =
2πe2
nh
The velocity of electron in the first orbit (i.e. when n = 1), also known as Bohr’s velocity is,
V1 = 2.19 × 108 cms-1
Which is 1/138 of velocity of light.
i.e. Vn = c/138n
iii. Energy of electron in different orbits En =
-2π2mz2e4 = -13.6 ev
n2h2 n2
- Energy of an electron is directly proportional to the square of n. i.e. En ∝ n2.
- Although the energy of an electron increases with increase in the value of n (orbit), yet the difference of energy between successive orbits decreases.
Thus, E2 – E1 > E3 – E2 > E4 – E3 etc.
iv. It could also explain the hydrogen spectra with following spectral lines :
a. Lyman series :
Lies in U-V region, Line appears in the atomic spectrum due to drops of electrons from higher energy levels to the lowest energy level (n1 = 1)
b. Balmer series :
Lies in visible region, Lines appear due to drop of electrons from energy levels 3, 4, 5, 6, .................. etc. to the energy level 2 (n1 = 2).
c. Similarly, the Paschen, Brakett and Pfund series :
Correspond to drop of electrons from higher energy levels 3, 4 and 5 respectively. These series lie in infrared region.
Limitations of Bohr’s model :
i. It does not explain the spectra of atoms having more than one electron.
ii. Bohr’s theory could not explain this multiple or fine structure of spectral lines.
iii. It does not explain the splitting of spectral lines into a group of finer lines under the influence of magnetic field (Zeeman’s effect) and electric field (Stark’s effect).
iv. This model could not obey de-Broglies hypothesis and Heisenberg’s uncertainty principle.
Bohr Sommerfield’s model :
In order to explain the fine spectrum sommerfield modified Bohr’s model and gave few postulates :
i. The path of electron is elliptical, circular path is the special case of elliptical path.
ii. Orbit is composed of sub – orbits ,
Number of sub orbits = orbit number.
De-Broglie’s Equation :
the momentum of a particle in motion is inversly proportional to the wavelength of the waves associated with it”.
i.e. λ ∝ (1/mv) ∴ λ = (h/mv)
thus the de broglie’s equation points out that every thing in nature posses the properties of particles as well as waves.
Heisenberg Uncertainity Principle :
It is impossible to determine simultaneously the position and momentum of microscopic particles with absolute certainity.” Mathematically,
Δx.Δp ≥ h/2π
Where, Δx = uncertainity in position, Δp = uncertainity in momentum.
Quantum Numbers :
The “state” of an electron in an atom is completely defined by a set of four numbers.
Here state refers to position, energy and orientation of electrons.
Four Quantum numbers are :
1. Principal Quantum numbers (n) :
It gives the idea about principal energy level to which electron belongs and the average distance between the electrons and nucleus higher the principal quantum number, greater is its size and also higher is its energy.
Though theoretically its value ranges from 1 to ∞ , only 1 to 7 are known, beyond 7, attraction between electron and nucleus is very small that atoms get ionized. They are distignated either as 1, 2, 3, 4, 5, 6 and 7 or K, L, M, N, O, P and Q respectively.
The maximum number of electrons in n principal quantum number is given by 2n2.
2. Azimuthal Quantum numbers (l) :
This number denotes the sub-shell to which the electron belongs and determines the shapes of the orbital and the energy associated with the angular momentum of the electron. For a given value of principal quantum number n, the azimuthal quantum number (l) may have all integral values from 0 to (n-1) each representing different sub-shell, denoted by s (sharp), p (principal), d (diffused) and f (fundamental).
Symbol of sub-shell :
s
p
d
F
Value of l
0
1
2
3

3. Magnetic Quanum numbers (m) :
4. Spin Quantum numbers (s) :

Tuesday

Volumetric Analysis (Acidimetry & Alkalimetry)

1. Titration : Titration is a process by means of which the concentration (strength) of a solution determined by allowing to react with a standard solution.
2. Acidimetry : It is the process by which strength of an acid is determined by reacting with a known amount (standard solution) of base in the presence of an indicator.
3. Alkalimetry : It is the process by which strength of an is alkali determined by reacting with a known amount (standard solution) of acid in presence of an indicator.
4. Standard Solution : A solution of definite concentration is called a standard solution. That is by standard solution we mean that a known amount of solute is dissolved in a given volume of solution. As an example 10gm of NaCl dissolved in 200ml solution is a standard solution.
5. Neutralization : The process of complete reaction of hydrogen ions of an acid with the exact amount of hydroxide ions of an alkali to form alkali molecules is called neutralization.It should be noted that neutralization does not mean that the resulting solution is always neutral. i.e. PH = 7 . In fact, when the same value of equivalent amount of acid and alkali reacts, it is said neutralization process has taken place.
6. Indicators : Indicators most frequcency used in acid base titration are methyl orange and phenolphthalein. Indicators are substance by which change colour and without reacting with solution indicate the end point we mean that equivalent amounts of substances have reacted.
Indicators also indicate whether a given solution is alkaline or neutral.

7. Some commonly used indicators and their PH Range :
Indicator                     Colour in A Med.            Colour in B. Med.            Pᴴ- Range
Methyl Orange                    Red                                   Yellow                          3.4 – 4.7
Phenolphthalein                  Colourless                            Pink                            8.2 – 10
Methyl Red                         Red                                    Yellow                         4.2 – 6.3
Litmus                                 Red                                     Blue                           5.5 – 8.0
Thymol blue base                Yellow                                 Blue                            8.0 – 9.6 

8. The choice of indicator in acid-alkali neutralization:
Acid           Alkali        PH-Range          Indicator       Solution in burette
Strong              Strong                  4 to 10            Ph. or M.Or. or litmus              Alkali
Strong              Weak                   3.5 to 7                M.Or. or M.R.                    Acid
Weak               Strong                 6.5 to 10                      PH                             Alkali
Weak               Weak                   No Sharp                    None           

9. Equivalent weight of some substance
         It is hoped that students are quite familiar with definitions of equivalent weight of acid, alkali, compound and salt. The equivalent weight of few substance are noteworthy Compound wt.                           Mol. Weight                     Equivalent HCl                                              36.5                                    36.5 HNO3                                           63.0                                   63.0 H2SO4                                           98.0                                 49.0 H2C2O4.2H2O                              126.0                                63.0 NaOH                                            40.0                                 40.0 KOH                                              56.0                                 56.0 CaO                                               56.0                                 28.0 Na2CO3.10H2O                             286.0                               143.0 Na2CO3                                         106.0                               53.0 NaHCO3                                        84.0                                 84.0 CaCO3                                           100.0                               50.0 MgCO3                                          84.0                                 84.0 NaCl                                              58.5                                 58.5 AgCl                                             143.5                                143.5 AgNO3                                          170.0                                170.0 BaSO4                                            233                                  116.5 NH4Cl                                            53.5                                  53.5 NH3                                                 17                                     17 10.     Concentration of Strength of solution
Relative amount of the solute and the solvent present in the solution. It is expressed in different units given below.
i.    Percentage strength          %(v/v),%(w/v) or %(w/w)
ii.    Gram per litre                               g/l
iii.    Normality                                     N
iv.    Molarity                                       M
v.    Molality                                        M
vi.    Mole Fraction                              X


i. Percentage strength :
a.     % by volume (w/v) :
It means that the weight of solute in grams dissolved per 100ml of its solution. Thus 2% NaCl solution means that 2gm NaCl is dissolved per 100ml of its solution.
% by volume =
Weight of solute (in gm) × 100
Volume of solution (in ml)
b.     % by weight (w/w) :
It express the weight of solute in grams dissolved per 100gm of its solution. As an examples 5% Na2CO3 by weight means that 5gm of Na2CO3 is displayed per 100gm of its solution.
% by weight =
 Weight of solute  ×100
   Volume of solution

ii. Gram per litre (g/l) :
The term itself implies the weight of solute in grams dissolved per litre or 100ml of its solution.
Gram per litre =
 Weight of solute (in gm)
 Volume of solution (in l)
         
 Weight of solute (in gm) × 1000
Volume of solution (in ml)

    iii.      Normality :
It is the number of gram equivalents of solute dissolved per litre solution. The numerical value is following by the letter N.
Thus 0.5 N solution means that the normality is 0.5, It than follows that 0.5 gram equivalent of solute is present in 1 L of solution.
Normal solution (1N) : it is the solution containing one gram equivalent of solute dissolved per litre of its solution.
Semi normal solution (N/2) : It is the equation containing half of the gram equivalent of solute per litre solution.W =
N(normality) × E(Eq. wt) ×V(ml)
                    1000
   iv.      Molarity :
It is the number of g-molecules (moles) of solute dissolved per litre its solution. As shown for normality, molarity, M =
W ×1000
V × MW
Where Mw is the molecular wt. of solute.
Molar solution (1M) : It is the solution containing one gm- molecule of the solute dissolved per litre solution.
v. Molality :
Molality is the number moles of the solute dissolved per 1 Kg or 1000gm of solvent.
If ‘a’ gm of solute of molecular weight MW is dissolved in “b” gm of solvent, then by definition, Molality =
a × 1000
MW × b
vi. Mole Fraction :
Mole fraction of a component in a solution is the ratio of the number of moles of that component and the number of moles of all the components in solution.
If a solution is prepared by dissolving nx mole of solute in ny mole of solvent, then
Xsolute = nx/(nx + ny)
Xsolvent = ny/(nx + ny)
Obviously; Xsolute+ Xsolvent = 1.0
11. Important :
- The most common mode of expressing concentration of a solution is molarity.
- Since mass does not change with rise in temperature, the value of molality, and mole fraction remains the same.
- As there in increase in volume by increase of temperature, the value of molarity and normality decreases when temperature is increased.
- When a certain volume of a standard solution is diluted (i.e. the volume is increased by addition of water) the concentration decreases.
- Normality and molarity of a solution is related as
Normality = molarity × mol. wt./eq. wt.
12. Normality factor :
It is the ratio of the weight of solute taken and the wt. of the solute required to prepare a solution of a particular strength.
Suppose 1.3gm of Na2CO3 is dissolved in 250 ml of a solution to prepare N/10 Na2CO3.By calculation the weight of Na2CO3 required = (250×53)/(10×1000) = 1.325 gm
Hence, by definition normality factor of N/10 Na2CO3.
Solution = 1.3/1.325= 0.98
The strength of solution =N/10 , (f = 0.98)
13. Basic principles of calculation :
1. When two solutions containing different solutes are able to different solutes are mixed and are to react together, it is the solutes present that react with themselves, water just speeds up the reaction.
2. Solutes completely react and products there by formed in a given reaction are always in proportion to their gm-equivalent.
3. If V1ml of a solution of strength N1 react completely with V2 ml of another solutes of strength N2, then their number gm-eq. of solute is
V1× N1 = V2× N2
4. Strength of a mixture : when different solution of the same nature and of given volume and strength are mixed, the principles (2) still holds
That is VmNm = V1N1+ V2N2+ V3N3+……………………….
When all solution are acids or alkalies, The subscript m stands for mixture, When acids and alkalies are mixed
VmNm = V1N1+ V2N2  _  V1N1+ V2N2  ……………………
                 Acids              Alkalies
5.     Acids and alkalies of the same strength in terms strength in terms of normality require the equal volume for neutralization.
Important formulae:
1. Strength in percentage = (gm/lit)/10.
2. Required amount (w) = (NEV)/1000.
3. Normality (N) = [(w/w)% × SP. gr × 10 ]/[eq. weight.]
4. Molarity (M) = [(w/w)% × SP. gr × 10 ]/[mol. weight.]
5. Normality (N) = [(w/v)% × 10 ]/[eq. weight.]
6. Molarity (M) = [(w/v)% × 10 ]/[mol. weight.]
7. N1V1 = N2V2
8. S1V1 = S2V2(only for dilution)
9. NV = N1V1+ N2V2+ N3V3
10.  M1V1 × Basicity = M2V2 × Acidity.